Integrand size = 26, antiderivative size = 90 \[ \int (e \sec (c+d x))^{3/2} (a+i a \tan (c+d x)) \, dx=-\frac {2 a e^2 E\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{d \sqrt {\cos (c+d x)} \sqrt {e \sec (c+d x)}}+\frac {2 i a (e \sec (c+d x))^{3/2}}{3 d}+\frac {2 a e \sqrt {e \sec (c+d x)} \sin (c+d x)}{d} \]
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Time = 0.09 (sec) , antiderivative size = 90, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {3567, 3853, 3856, 2719} \[ \int (e \sec (c+d x))^{3/2} (a+i a \tan (c+d x)) \, dx=-\frac {2 a e^2 E\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{d \sqrt {\cos (c+d x)} \sqrt {e \sec (c+d x)}}+\frac {2 i a (e \sec (c+d x))^{3/2}}{3 d}+\frac {2 a e \sin (c+d x) \sqrt {e \sec (c+d x)}}{d} \]
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Rule 2719
Rule 3567
Rule 3853
Rule 3856
Rubi steps \begin{align*} \text {integral}& = \frac {2 i a (e \sec (c+d x))^{3/2}}{3 d}+a \int (e \sec (c+d x))^{3/2} \, dx \\ & = \frac {2 i a (e \sec (c+d x))^{3/2}}{3 d}+\frac {2 a e \sqrt {e \sec (c+d x)} \sin (c+d x)}{d}-\left (a e^2\right ) \int \frac {1}{\sqrt {e \sec (c+d x)}} \, dx \\ & = \frac {2 i a (e \sec (c+d x))^{3/2}}{3 d}+\frac {2 a e \sqrt {e \sec (c+d x)} \sin (c+d x)}{d}-\frac {\left (a e^2\right ) \int \sqrt {\cos (c+d x)} \, dx}{\sqrt {\cos (c+d x)} \sqrt {e \sec (c+d x)}} \\ & = -\frac {2 a e^2 E\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{d \sqrt {\cos (c+d x)} \sqrt {e \sec (c+d x)}}+\frac {2 i a (e \sec (c+d x))^{3/2}}{3 d}+\frac {2 a e \sqrt {e \sec (c+d x)} \sin (c+d x)}{d} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 1.01 (sec) , antiderivative size = 102, normalized size of antiderivative = 1.13 \[ \int (e \sec (c+d x))^{3/2} (a+i a \tan (c+d x)) \, dx=\frac {2 a e e^{-2 i d x} \sqrt {e \sec (c+d x)} (\cos (c+3 d x)+i \sin (c+3 d x)) \left (-2 i+i \sqrt {1+e^{2 i (c+d x)}} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {3}{4},\frac {7}{4},-e^{2 i (c+d x)}\right )+\tan (c+d x)\right )}{3 d} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 410 vs. \(2 (105 ) = 210\).
Time = 3.33 (sec) , antiderivative size = 411, normalized size of antiderivative = 4.57
method | result | size |
default | \(\frac {2 a \left (i F\left (i \left (\csc \left (d x +c \right )-\cot \left (d x +c \right )\right ), i\right ) \sqrt {\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}\, \sqrt {\frac {1}{\cos \left (d x +c \right )+1}}\, \left (\cos ^{2}\left (d x +c \right )\right )-i E\left (i \left (\csc \left (d x +c \right )-\cot \left (d x +c \right )\right ), i\right ) \sqrt {\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}\, \sqrt {\frac {1}{\cos \left (d x +c \right )+1}}\, \left (\cos ^{2}\left (d x +c \right )\right )+2 i \cos \left (d x +c \right ) F\left (i \left (\csc \left (d x +c \right )-\cot \left (d x +c \right )\right ), i\right ) \sqrt {\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}\, \sqrt {\frac {1}{\cos \left (d x +c \right )+1}}-2 i \cos \left (d x +c \right ) E\left (i \left (\csc \left (d x +c \right )-\cot \left (d x +c \right )\right ), i\right ) \sqrt {\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}\, \sqrt {\frac {1}{\cos \left (d x +c \right )+1}}+i F\left (i \left (\csc \left (d x +c \right )-\cot \left (d x +c \right )\right ), i\right ) \sqrt {\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}\, \sqrt {\frac {1}{\cos \left (d x +c \right )+1}}-i E\left (i \left (\csc \left (d x +c \right )-\cot \left (d x +c \right )\right ), i\right ) \sqrt {\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}\, \sqrt {\frac {1}{\cos \left (d x +c \right )+1}}+\sin \left (d x +c \right )\right ) \sqrt {e \sec \left (d x +c \right )}\, e}{d \left (\cos \left (d x +c \right )+1\right )}+\frac {2 i a \left (e \sec \left (d x +c \right )\right )^{\frac {3}{2}}}{3 d}\) | \(411\) |
parts | \(\frac {2 a \left (i F\left (i \left (\csc \left (d x +c \right )-\cot \left (d x +c \right )\right ), i\right ) \sqrt {\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}\, \sqrt {\frac {1}{\cos \left (d x +c \right )+1}}\, \left (\cos ^{2}\left (d x +c \right )\right )-i E\left (i \left (\csc \left (d x +c \right )-\cot \left (d x +c \right )\right ), i\right ) \sqrt {\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}\, \sqrt {\frac {1}{\cos \left (d x +c \right )+1}}\, \left (\cos ^{2}\left (d x +c \right )\right )+2 i \cos \left (d x +c \right ) F\left (i \left (\csc \left (d x +c \right )-\cot \left (d x +c \right )\right ), i\right ) \sqrt {\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}\, \sqrt {\frac {1}{\cos \left (d x +c \right )+1}}-2 i \cos \left (d x +c \right ) E\left (i \left (\csc \left (d x +c \right )-\cot \left (d x +c \right )\right ), i\right ) \sqrt {\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}\, \sqrt {\frac {1}{\cos \left (d x +c \right )+1}}+i F\left (i \left (\csc \left (d x +c \right )-\cot \left (d x +c \right )\right ), i\right ) \sqrt {\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}\, \sqrt {\frac {1}{\cos \left (d x +c \right )+1}}-i E\left (i \left (\csc \left (d x +c \right )-\cot \left (d x +c \right )\right ), i\right ) \sqrt {\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}\, \sqrt {\frac {1}{\cos \left (d x +c \right )+1}}+\sin \left (d x +c \right )\right ) \sqrt {e \sec \left (d x +c \right )}\, e}{d \left (\cos \left (d x +c \right )+1\right )}+\frac {2 i a \left (e \sec \left (d x +c \right )\right )^{\frac {3}{2}}}{3 d}\) | \(411\) |
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.07 (sec) , antiderivative size = 116, normalized size of antiderivative = 1.29 \[ \int (e \sec (c+d x))^{3/2} (a+i a \tan (c+d x)) \, dx=-\frac {2 \, {\left (\sqrt {2} {\left (3 i \, a e e^{\left (3 i \, d x + 3 i \, c\right )} + i \, a e e^{\left (i \, d x + i \, c\right )}\right )} \sqrt {\frac {e}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} e^{\left (\frac {1}{2} i \, d x + \frac {1}{2} i \, c\right )} + 3 \, \sqrt {2} {\left (i \, a e e^{\left (2 i \, d x + 2 i \, c\right )} + i \, a e\right )} \sqrt {e} {\rm weierstrassZeta}\left (-4, 0, {\rm weierstrassPInverse}\left (-4, 0, e^{\left (i \, d x + i \, c\right )}\right )\right )\right )}}{3 \, {\left (d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )}} \]
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\[ \int (e \sec (c+d x))^{3/2} (a+i a \tan (c+d x)) \, dx=i a \left (\int \left (- i \left (e \sec {\left (c + d x \right )}\right )^{\frac {3}{2}}\right )\, dx + \int \left (e \sec {\left (c + d x \right )}\right )^{\frac {3}{2}} \tan {\left (c + d x \right )}\, dx\right ) \]
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\[ \int (e \sec (c+d x))^{3/2} (a+i a \tan (c+d x)) \, dx=\int { \left (e \sec \left (d x + c\right )\right )^{\frac {3}{2}} {\left (i \, a \tan \left (d x + c\right ) + a\right )} \,d x } \]
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\[ \int (e \sec (c+d x))^{3/2} (a+i a \tan (c+d x)) \, dx=\int { \left (e \sec \left (d x + c\right )\right )^{\frac {3}{2}} {\left (i \, a \tan \left (d x + c\right ) + a\right )} \,d x } \]
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Timed out. \[ \int (e \sec (c+d x))^{3/2} (a+i a \tan (c+d x)) \, dx=\int {\left (\frac {e}{\cos \left (c+d\,x\right )}\right )}^{3/2}\,\left (a+a\,\mathrm {tan}\left (c+d\,x\right )\,1{}\mathrm {i}\right ) \,d x \]
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